The value of y is `(x-sqrt(x^2-1))^m`

If 2x = sqrt(a) - (1)/(sqrt(a)) , then the value of (sqrt(x^(2) + 1))/(x + sqrt(x^(2) +1)) is

If x*y=sqrt(x^2+y^2) the value of (1*2 sqrt 2)(1*-2 sqrt 2) is

Find the value of int((x^m-1)dx)/(x^(m+1)sqrt(1-2x^m+mx^(2m))) (A) sqrt(m+2/x^m+1/x^(2m)+c) (B) sqrt(m-2/x^m+1/x^(2m)+c) (C) sqrt(m-2/x^m-1/x^(2m)+c) (D) sqrt(m+2/x^m-1/x^(2m)+c)

The value of f(x,y)=((4sqrt(x^(3)y)-4sqrt(x^(3)))/(sqrt(y)-sqrt(x))+(1+sqrt(xy))/(4sqrt(xy)))^(-2)(1+2sqrt((y)/(x))+(y)/(x))^((1)/(2)) when x=9,y=0.04

if x is very large as compare to y,then the value of k in sqrt((x)/(x+y))sqrt((x)/(x-y))=1+(y^(2))/(kx^(2))

If x ,y in R satify the equation x^2+y^2-4x-2y+5=0, then the value of the expression [(sqrt(x)-sqrt(y))^2+4sqrt(x y)]//(x+sqrt(x y)) is sqrt(2)+1 b. (sqrt(2)+1)/2 c. (sqrt(2)-1)/2 d. (sqrt(2)+1)/(sqrt(2))

If x ,y in R satify the equation x^2+y^2-4x-2y+5=0, then the value of the expression [(sqrt(x)-sqrt(y))^2+4sqrt(x y)]//(x+sqrt(x y)) is a. sqrt(2)+1 b. (sqrt(2)+1)/2 c. (sqrt(2)-1)/2 d. (sqrt(2)+1)/(sqrt(2))

If x ,y in R satify the equation x^2+y^2-4x-2y+5=0, then the value of the expression [(sqrt(x)-sqrt(y))^2+4sqrt(x y)]//(x+sqrt(x y)) is a. sqrt(2)+1 b. (sqrt(2)+1)/2 c. (sqrt(2)-1)/2 d. (sqrt(2)+1)/(sqrt(2))

The point (x,y) lies on the line 2x+3y=6 . The smallest value of the quantity sqrt(x^(2)+y^(2)) is m. then the value of sqrt(13)m is

The point (x,y) lie on line 2x+3y=6. The smallest value of the quantitly sqrt(x^2+y^2 " is m. The the value of " sqrt13m is _______