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A square loop EFGH of side a, mass m and...

A square loop EFGH of side a, mass m and total resistance R is falling under gravity in a region of transverse non - uniform magnetic field given by `B=B_(0)^(y)/(a)` =, where `B_(0)` is a positive constant and y is the position of side EF of the loop. If at some instant the speed of the loop is v, then the total Lorentz acting on the loop is

A

`F=(B_(0)^(2)a^(2)v)/(2H)`

B

`F=(2B_(0)^(2)a^(2)v)/(R)`

C

`F=(B_(0)^(2)a^(2)v)/(R)`

D

zero

Text Solution

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The correct Answer is:
C
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