Home
Class 12
PHYSICS
In figure the electric field using Gauss...

In figure the electric field using Gauss law the Formula `|vec(E)|=(q_("enc"))/(in_(0)|A|)` is applicable. In the formula. `in_(0)` is permittivity free space, A is the area of Gaussian surface and `q_("enc")` is charge enclosed by the Gaussion surface. This equation can be used in which of the following situation?

A

Only when the Gaussian surface is an equipotential surface

B

only when `|vecE|` is constant on the surface

C

only when the the Gaussian surface is an equipotential surface `|vecE|` is constant of the surface

D

for any choice of Gaussian surface

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • JEE MOCK TEST 7

    NTA MOCK TESTS|Exercise PHYSICS - Subjective Numerical|5 Videos
  • JEE MOCK TEST 9

    NTA MOCK TESTS|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

In FIGUREinding the electric FIGUREield using Gauses law the FIGUREormula |vec(E)|=(q_("enc"))/(in_(0)|A|) is applicable. In the FIGUREormula. in_(0) is permittivity oFIGURE FIGUREree space, A is the area oFIGURE Gaussian surFIGUREace and q_("enc") is charge enclosed by the Gaussion surFIGUREace. This equation can be used in which oFIGURE hte FIGUREollowing situation?

If electric field around a surface is given by |vec(E)|=(Q_(in))/(epsilon_0|A|) where 'A' is the normal area of surface and Q_(in) is the charge enclosed by the surface. This relation of gauss's law is valid when

The dimensions of (1)/(2) in_(0) E^(2) , where in_0 is permittivity of free space and E is electric field, is :-

The dimensions of 1/2 in_(0) E^(2) ( in_(0) : permittivity of free space, E: electric field) is-

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . A Gaussian surface encloses two of the four positively charged particles. The particles that contribute to the electric field at a point P on the surface are

q_(1),q_(2),q_(3) and q_(4) are point charges located at point as shown in the figure and s is a spherical Gaussian surface of radius R . Which of the following is true according to the Gauss's law

The dimensional formula for permittivity of free space (epsilon_0) in the equation F ==1/(4piepsilon_0),(q_1q_2)/(r^2) , where symbols have usual meaning is

Assertion:- In a given situation of arrangement of charges, an extra charge is placed outside the Gaussion surface. In the Gauss Theroem ointvecEdvecs=(Q_(in))/(epsilon_(0))Q_(in) remains unchanged whereas electric field vecE at the site of the element is changed. Reason:- Electric field vecE at any point on the Gaussian surface is due to inside charge only.

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . The net flux of the electric field through the surface due to q_(3) and q_(4) is

Gauss's law and Coulomb's law , although expressed in different forms , are equivalent ways of describing the relation between charge and electric field in static conditions . Gauss's law is epsilon_(0) phi = q_(encl) ,when q(encl) is the net charge inside an imaginary closed surface called Gaussian surface. The two equations hold only when the net charge is in vaccum or air . The net flux of the electric field through the surface is

NTA MOCK TESTS-JEE MOCK TEST 8-PHYSICS
  1. A particle is projected from the ground and simultaneously a wedge sta...

    Text Solution

    |

  2. A square loop EFGH of side a, mass m and total resistance R is falling...

    Text Solution

    |

  3. N molecules each of mass m of gas A and 2 N molecules each of mass 2m ...

    Text Solution

    |

  4. Two particles of equal mass m are moving with velocities vhati and v((...

    Text Solution

    |

  5. A block of mass 200 kg is being pulled by some men, up an inclined pla...

    Text Solution

    |

  6. In a uniform magnetic field of strength 0.15 T, a short bar magnet of ...

    Text Solution

    |

  7. The current I(1) (in A) flowing through the 1Omega resistor in the giv...

    Text Solution

    |

  8. In figure the electric field using Gauss law the Formula |vec(E)|=(q("...

    Text Solution

    |

  9. An inverted bell lying at the bottom of a lake 47.6 m deep has 50 cm^3...

    Text Solution

    |

  10. A simple pendulum is being used to determine the value of gravitationa...

    Text Solution

    |

  11. A bar of mass m and length l is in pure translational motion with its ...

    Text Solution

    |

  12. The given figure shows the elliptical orbit of a planet m about the su...

    Text Solution

    |

  13. The speed of sound in hydrogen gas at N.T.P is 1328ms^(-1). If the den...

    Text Solution

    |

  14. Equation of motion for a particle performing damped harmonic oscillati...

    Text Solution

    |

  15. If an electron in a hydrogen atom is in its 2^("nd") excited state, or...

    Text Solution

    |

  16. IF B is the magnetic field at the centre of a circular loop of area A ...

    Text Solution

    |

  17. In young's double slit experiment using monochromatic light of wavelen...

    Text Solution

    |

  18. A plano - convex lens has diameter 5 cm and its thickness at the centr...

    Text Solution

    |

  19. In a special arrangement of Young's double - slits d is twice the dist...

    Text Solution

    |

  20. A series combination of n(1) capacitors, each of value C(1), is charge...

    Text Solution

    |