An inverted bell lying at the bottom of ...

An inverted bell lying at the bottom of a lake `47.6 m` deep has `50 cm^3` of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be (atmospheric pressure `= 70 cm` of `Hg` and density of `Hg = 13.6 g//cm^3`).

`600cm^(3)`

`300cm^(3)`

`250cm^(3)`

`200cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

JEE MOCK TEST 7
NTA MOCK TESTS|Exercise PHYSICS - Subjective Numerical|5 Videos
JEE MOCK TEST 9
NTA MOCK TESTS|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

Radius of an air bubble at the bottom of the lake is r and it becomes 2 r when the air bubbles rises to the top surface of the lake. If P cm of water be the atmospheric pressure, then the depth of the lake is

An air bubble starts rising from the bottom of a lake. Its diameter is 3.6 mm at the bottom and 4 mm at the surface. The depth of the lake is 250 cm and the temperature at the surface is 40^@ C . What is the temperature at the bottom of the lake? Given atmospheric pressure = 76 cm of Hg and g = 980 cm//s^2 .

The temperature at the bottom of a 40 cm deep lake is 12^(@)C and that at the surface is 35^(@)C . An air bubble of volume 1.0 cm^(3) rises from the bottom to the surface. Its volume becomes (atmospheric pressure = 10 m of water)

Calculate the kinetic energy per unit volume of a gas at a pressure of 10mm of Hg . (Density of Hg=13.6xx10^(3)kgm^(-3) and g=9.8ms^(-2) )

A quill tube contains a mercury column of length 19cm . The length of air column is 24cm when it is held veritcally. On inverting it with its open end downwards the length of air column will be (atmospheric pressure = 76cm of Hg )

NTA MOCK TESTS-JEE MOCK TEST 8-PHYSICS

A particle is projected from the ground and simultaneously a wedge sta...
Text Solution
|
A square loop EFGH of side a, mass m and total resistance R is falling...
Text Solution
|
N molecules each of mass m of gas A and 2 N molecules each of mass 2m ...
Text Solution
|
Two particles of equal mass m are moving with velocities vhati and v((...
Text Solution
|
A block of mass 200 kg is being pulled by some men, up an inclined pla...
Text Solution
|
In a uniform magnetic field of strength 0.15 T, a short bar magnet of ...
Text Solution
|
The current I(1) (in A) flowing through the 1Omega resistor in the giv...
Text Solution
|
In figure the electric field using Gauss law the Formula |vec(E)|=(q("...
Text Solution
|
An inverted bell lying at the bottom of a lake 47.6 m deep has 50 cm^3...
Text Solution
|
A simple pendulum is being used to determine the value of gravitationa...
Text Solution
|
A bar of mass m and length l is in pure translational motion with its ...
Text Solution
|
The given figure shows the elliptical orbit of a planet m about the su...
Text Solution
|
The speed of sound in hydrogen gas at N.T.P is 1328ms^(-1). If the den...
Text Solution
|
Equation of motion for a particle performing damped harmonic oscillati...
Text Solution
|
If an electron in a hydrogen atom is in its 2^("nd") excited state, or...
Text Solution
|
IF B is the magnetic field at the centre of a circular loop of area A ...
Text Solution
|
In young's double slit experiment using monochromatic light of wavelen...
Text Solution
|
A plano - convex lens has diameter 5 cm and its thickness at the centr...
Text Solution
|
In a special arrangement of Young's double - slits d is twice the dist...
Text Solution
|
A series combination of n(1) capacitors, each of value C(1), is charge...
Text Solution
|