A 44 mH inductor is connected to 220 V, 50 Hz a.c. supply. Determine rms value of current in the circuit.

Explanation

Inductance of inductor, `L=44mH=44xx10^(-3)H`
Supply voltage, V=220V
Frequency, v=50V
Angular frequenc, `omega=2piv`
Inductive reactivance, `x_(L)= 2pivL=2pixx50xx44xx10^(-3)Omega`
Rms value of current is given as:
`=(220)/(2pixx50xx44xx10^(-3))=15.92A`
Hence, the rms value of current in the circuit is 15.92A.