In Exercises 7.3 and 7.4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.

Explanation

In the inducive circuit,
Rms value of current, I=15.92A
Rms value of voltage,V=220V
Hence, the net power absorbed can be obtained by the relation
`P=VI cos phi`
Where,
`phi=` phase difference between V and I
For a pure inductive circuit, the phase difference between alternating voltage and current is `90^(@)i.e., phi=90^(@)`
Hence, P= 0 i.e., the net power is zero.
In the capacitive circuit,
In the capacitive circuit,
Rms value of cur4rent, `I=2.49A `
Rms value of voltage=V=110V
Hence, the net power absorbed can ve obtained as:
`P=VI cos phi`
For a pure capacitvi e circ uit, the phase different between alternating voltage and current `90^(@) i.e., phi=90^(@)`
Hence, p= 0 i.e., the net power is zero.