At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is `100 m^(3) s^(-1)`. If the turbine generator efficiency is 60%, estimate the electric power available from the plant `(g = 9.8 ms^(-2))`.

Explanation

Height of water pressure head, h=300m
volume of water flow per second, `V=100m^(3)//s`
Efficiency of turbine generator, n=60% =0.6
Accelration due to gravity, g=`9.8m//s^(2)`
Density of water, `rho=10^(3)kg//m^(3)`
Electric power available from the plant`=etaxxhpgV`
`0.6xx300xx10^(3)xx9.8x x100`
`=176.4xx10^(6)W`
`=176.4MW`