The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is `B_0=510 nT`. What is the amplitude of the electric field part of the wave?

Explanation

Energy of a photon is given as:
`E=hv=(hc)/(gamma)`
Where,
h=planck's constant =`606xx10^(-34)Js`
c=speed of light=`3xx10^(8)m//s`
`gamma`= Wavelength of radiation.
`thereforeE=(6.6xx10^(-34)xx3xx10^(8))/(gamma)=(19.8xx10^(-26))/(gamma)J`
`=(19.8xx10^(-26))/(gammaxx1.6xx10^(-19))=(12.375xx10^(-7))/(gamma)eV`
The given table lists the photon energies for different parts of an electromagnetic spectrum for differents.