(i) `81^(1/2)`

The value of [{(81)^(-1/2)}^(-1/4)]^2

If the first term of a G.P is 27 and 8th term is 1/81 , then the sum of its first 10 terms is (i) 27/2(1-1/(3^(10))) (ii) 81/2(1/(3^(10))-1) (iii) 27/2(1/(3^(10))-1) (iv) 81/2(1-1/(3^(10)))

Evaluate each of the following : (i){(81)^(1//5)}^(5//2)" "(ii)(3sqrt(64))^(-2)" "(iii)9^(3//2)+3xx4^(0)-((1)/(81))^(-1//2) (vi)sqrt((1)/(9))+(0.01)^(-1//2)-(27)^(4//3)" "(v)((125)/(64))^(2//3)+((256)/(625))^(-1//4)

9^(3/2)+3xx4^(0)-((1)/(81))^(-1/2)

4xx81^(-1/2)xx(81^(1/2)+81^(3/2))

Prove that: 9^(3//2)-3xx5^0-(1/81)^(-1/2)=15

Prove that: 9(3)/(2)quad -3x5^(0)-((1)/(81))^(-(1)/(2))=15

Evaluate : 9^((5)/(2)) - 3xx8^(0)-((1)/(81))^(-(1)/(2))

Prove that: 9^(3/2\ )-\ 3\ xx\ 5^0-\ (1/(81))^(-1/2)=15

If [(27)^((2)/(3))-(81)^((1)/(2))]^(a)=0 then which of the following cannot be the value of a: