`(sin theta)/(1-cos theta)=(1+cos theta)/(sin theta)`

1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin theta)/(1-cos theta) - (1)/(sec theta)=

1-(sin^(2)theta)/(1+cos theta)+(1+cos theta)/(sin theta)-(sin theta)/(1-cos theta) equals

(sin theta)/(1+cos theta) is equal to (1+cos theta)/(sin theta)(b)(1-cos theta)/(cos theta)(c)(1-cos theta)/(sin theta) (d) (1-sin theta)/(cos theta)

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

prove that (cos theta)/(1-sin theta)+(cos theta)/(1+sin theta)=(2)/(cos theta)

Prove (cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

(cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

Prove the following identity : (sin theta)/(1+cos theta)+ (sin theta)/(1-cos theta)= 2/(sin theta) .

(sin theta)/(1+cos theta)+(sin theta)/(1-cos theta)= _______