[2x+3y=8],[x-2y+3=0]

Solve [2x+3y-7=0],[3x+2y-8=0]

Solve: 2x+3y=2; x-2y=8

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

Prove that the lies 3x+y-14=0,\ x-2y=0\ n a d\ 3x-8y+4=0 are concurrent.

Prove that the lies 3x+y-14=0,x-2y=0 nad 3x-8y+4=0 are concurrent.

3x+2y=8 2x-3y=8

3x+2y=8 2x-3y=1

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

find x and y : 2x+3y-8=0, 3x+y-5=0