Find the mean deviation about the median of the following frequency distribution: Class:, 0-6, 6-12, 12-18, 18-24, 24-30 Frequency:, 8, 10, 12, 9, 5

Explanation

Here,` N = 20. So,N/2=10`

The cummulative frequency just greater than
is `12`.

Thus,` 12–18` is the median class.


Now,` l = 12, h = 6, f = 3` and `F = 9`

So,median`=L+(N/2-F)/fXh`

`=12+(10-9)/3X6`

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