" If "10^(x)=(1)/(2)," then "10^(8x)=?

If f'(x)=8x^(3)+3x^(2)-10x-k " and " f(0)=-3,f(-1)=0," then " f(x)= is

If x^(2)+(1)/(x^(2))=102, then x-(1)/(x)=8( b) 10 (c) 12 (d) 13

If x^2+1/(x^2)=102 , then x-1/x=? (a)8 (b) 10 (c) 12 (d) 13

If x+(1)/(x)=2costheta" then "x^(10)+(1)/(x^(10))

If K^(@) lies between 360^(@) and 540^(@) and K^(@) satisfies the equation 1+cos10x cos6x =2cos^(2)8x+sin^(2)8x," then "(K)/(10)=

If K^(@) lies between 360^(@) and 540^(@) and K^(@) satisfies the equation 1+cos10x cos6x =2cos^(2)8x+sin^(2)8x," then "(K)/(10)=

If K^(@) lies between 360^(@) and 540^(@) and K^(@) satisfies the equation 1+cos10x cos6x =2cos^(2)8x+sin^(2)8x," then "(K)/(10)=

The inverse of f(x)=(10^(x)-10^(-x))/(10^(x)+10^(-x)) is A). (1)/(2)log_(10)((1+x)/(1-x)) , B). log_(10)(2-x) , C). (1)/(2)log_(10)(2-1) , D). (1)/(4)log_(10)((2x)/(2-x))

" If (3x^(3)-8x^(2)+10)/((x-1)^(4))=(3)/(x-1)+(1)/((x-1)^(2))-(7)/((x-1)^(3))+(k)/((x-1)^(2)) then "k=