If A,B,C,D are the four angles taken in order of a cyclic quadrilateral prove that tan A+tan B+tan C+tan D=0

If A,B,C,D are the four angles taken in order of a cyclic quadrilateral prove that (i)tan A+tan B+tan C+tan D=0 (ii) cos(180^(@)-A)+cos(180^(@)+B)+cos(180-C^(@))-sin(90+D)tan(A+B)+tan(C+D)=0tan(A+B)+tan(C+D)=0

If A,B,C,D are angles of a cyclic quadrilateral,prove that cos A+cos B+cos C+cos D=0

If A,B,C,D are angles of a cyclic quadrilateral,then prove that cos A+cos B+cos C+cos D=0

If A, B, C, D be the angles of a quadrilateral, prove that : (tanA+tanB+tanC+tanD)/(cotA+cotB+cotC+cotD) = tan A tan B tan C tan D

If A+C=B , then tan A tan B tan C = ?

If ABCD is a cyclic quadrilateral, then tan A +tan C =_________.

(a) tan A+tan B+tan C=tan A tan B tan C

If A,B,C,D are the angles of a quadrilateral, then (tan A+tan B+tan C+tan D)/(cot A+cot B+cot C+cot D) is equal to: (a) tan A tan B tan C tan D(b)tan^(2)A+tan^(2)B+tan^(2)C+tan^(2)D(d)sum tan A tan B tan C

If A+B+C= pi/2 , prove that tan A tan B+tan B tan C+tan C tan A=1