`log(x-1)+log(x-2)lt log(x+2)`

Statement - 1 : If x gt 1 then log_(10)x lt log_(3)x lt log_(e )x lt log_(2)x . Statement - 2 : If 0 lt x lt 1 , then log_(x)a gt log_(x)b implies a lt b .

lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))= _______.

Solve for real value of x: log (x - 1) + log (x^(2) + x+ 1) = log 999 .

log5-log(x+10)-1=log(21x-20)-log(2x-1)

log5+log(x+10)-1=log(21x-20)-log(2x-1)

If 0

log(x) -log(2x-3)=1 then x = ?

int (dx)/((x+1)(x-2))=A log (x+1)+B log (x-2)+C , where

log x-(1)/(2)log(x-(1)/(2))=log(x+(1)/(2))-(1)/(2)log(x+(1)/(8))