Dimensional formula for `((h^(2)v^(2))/(mc^(2)))/(1+(hv)/(mc^(2)))` is (where h is planck's constant v is frequency of light m is mass and c is speed of light).

(1)/(2)mc^(2)(alpha)T

A photon has an energy where h is the Planck's constant, v is the frequency of radiation, lamda is the wavelength of radiation, and c is the velocity of light.

Show that h/(m_0c) is of the dimensions of length where h is Planck constant , m_0 , rest mass and c, velocity of light.

n=(v)/(c) where n denotes the refractive index of a medium, v the speed of light in the medium and c the speed of light in vacuum.

The maximum velocity of an electron emitted by light of wavelength lambda incident on the surface of a metal of work function phi , is Where h = Planck's constant , m = mass of electron and c = speed of light.

If the energy of a photon is given by E =(hc)/(lambda) , where h is the Plank's constant c is the velocity of light and lambda is the wavelength of the radiation then the unit of Planck's constant is "______"

The dimension of the quantity 1/epsilon_0 e^2/(hc) is (e charge of electron,h Planck's constant and c=velocity of light)

What is the dimensional formula for mc^(2) , where m and c denote the mass and velocity of a body?

The dimensions of length are expressed as G^(x)c^(y)h^(z) , where G, c and h are the universal gravitational constant, speed of light and Planck's constant respectively, then :