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Show that: {i^(19)+(1/i)^(25)}^2=-4 (ii)...

Show that: `{i^(19)+(1/i)^(25)}^2=-4` (ii) `{i^(17)-(1/i)^(34)}^2=2i` (iii) `{i^(18)+(1/i)^(24)}^3=0` (iv) `i^n+i^(n+1)+i^(n+2)+i^(n+3)=0` for all `n in Ndot`

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Show that : (i) {i^(19) + (1/i)^(25)}^(2) = -4 " "(ii) {i^(17) - (1/i)^(34)}^(2) = 2i (iii) {i^(18) + (1/i)^(24)}^(3) = 0 " " (iv) i^n + i^(n+1) + i^(n +2) + i^(n + 3) = 0 , for all n in N .

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