[(bx)/(g)(ay)/(b)+a+b=0],[x-yy+2ab=0]

Solve the following system of equations b(x)/(a)-a(y)/(b)+a+b=0,bx-ay+2ab=0

(bx)/(a)-(ay)/(b)+a+b=0 and bx-ay+2ab

(bx ) /(a) + ( ay ) /( b) = a ^(2) + b ^(2) , x + y = 2ab

The equation of a line perpendicular to line ax+by+c=0 and passing through (a,b) is equal to ................ A) bx-ay=0 B) bx+ay-2ab=0 C) bx+ay=0 D) bx-ay+ 2ab=0

Solve (by any method) : (x+a)/(2a+b)=(y+2b)/(a+b) bx+ay=a^(2)+b^(2)

If (ax+by)/(x+y)=(bx+az)/(x+z)=(ay+bz)/(y+z) and x+y+z=!0 then show that each ratio is (a+b)/2

A circle with center (a,b) passes through the origin.The equation of the tangent to the circle at the origin is ax-by=0 (b) ax+by=0bx-ay=0 (d) bx+ay=0

The straight line x-y-2=0 cuts the axis of x at A. It is rotated about A in such a manner that it is perpendicular to ax+by+c=0. Its equation is: (a) bx-ay-2b=0 (b) ax-by-2a=0 (c) bx+ay-2b=0 (d) ax+by+2a=0

If (x)/(a)+(y)/(b)=1 intersects 5x^(2)+5y^(2)+5bx+5ay-9ab=0 at P and Q,/_POQ=(pi)/(2) then the relation between a and b is (A) a=b(B)a=2b or b=2a(C)a=3b or b=3a(D)a+b=5

Solve the following system of equations in x and yax+by=1bx+ay=((a+b)^(2))/(a^(2)+b^(2))-1 or,bx+ay=(2ab)/(a^(2)+b^(2))