(03+0.7x)/(x)=0.95

(0.3+0.7x)/(x)=0.95

Solve : 0.25+(1.95)/(x)=0.9

IF X to B ( n= 20,p=0.03) and (0.97)^(20) = 0.5437 then : P ( X ge 1)=

If f(x)={[(sin7x)/(3x),x!=0 or m if x=0]} is continuous at x=0 then value of m is (a) 3/7 (b) 4/7 (c) 7/4 (d) 7/3

If f(x)={[(sin7x)/(3x),x!=0 or m if x=0]} is continuous at x=0 then value of m is (a) 3/7 (b) 4/7 (c) 7/4 (d) 7/3

If f(x)={[(sin7x)/(3x),x!=0 or m if x=0]} is continuous at x=0 then value of m is (a) 3/7 (b) 4/7 (c) 7/4 (d) 7/3

Complete set of solution of equation (log_(0.3)(x-2))/(|x|)>=0

The maximum value of the function f(x)=(1+x)^(0.3)/(1+x^(0.3)) in [0,1] is

The maximum value of the function f(x)=(1+x)^(0.3)/(1+x^(0.3)) in [0,1] is