If `n=10 , X =12` and `sumx_(12)=1530 ,` then the coefficient of variation is

Options

A. `36% `
B. `41% `
C. `25%`
D. none of these

Answer

C

Explanation

Here,` n = 10, barX = 12, sum x_i^2 = 1530`

`:.` Variance `(sigma)^2 = 1/n (sum (x_i^2 - (barX)^2)`

`=>sigma^2 = 1/10(1530 - 10(12)^2) = 90/10 = 9 `

`:.` Standard deviation `(sigma) = sqrt9 = 3`

Now, we will calculate coefficient of variation which is given by,

`C.V. = (sigma)/(barX)**100`

`:. C.V. = 3/12**100 = 25%.`