`inttan(3x-5)sec(3x-5)dx` is equal to (A) `sec(3x-5)+c` (B) `1/3sec(3x-5)+c` (C) `tan(3x-5)+c` (D) none

inttan^(-1)(sec3x+tan3x)dx=

sec^(2) (x)/(5) + 18 cos 2 x + 10 sec (5 x + 3) tan (5x + 3 )

int(sin5x)/(cos7xcos2x)dx is equal to (A) log|sec7x|+c (B) log|sec7xsec2x|+c (C) log|sec7x+sec2x|+c (D) none of these

int(sin5x)/(cos7xcos2x)dx is equal to (A) log|sec7x|+c (B) log|sec7xsec2x|+c (C) log|sec7x+sec2x|+c (D) none of these

int sec^(3)x tan^5 xdx

int(3e^(x)-(1)/(5x)+sec x-tan x)dx

inttan2x. tan3x. tan5x dx =

int( (log x)^(5) )/( x ) dx is equal to a) (log x^(6))/( 6) + C b) ( ( log x )^(6))/( 6) + C c) ((log x )^(6))/( 3x^(2)) + C d) none of these

Evaluate : int sec^2(3x + 5)dx