If `2f(x)-3f(1/x)=x^2(x!=0),` then `f(2)` is equal to (a)`-7/4("b")""5/2` (c) -1 (d) none of these

Explanation

`2f(x) - 3f(1/x) = x^2`

When `x = 2`,

`2f(2)-3f(1/2) = 4 ->(1)`

When `x = 1/2`,

`2f(1/2) - 3f(2) = 1/4->(2)`

Nw, multiplying (1) with `2` and (2) with `3` and then adding (1) and (2),

`4f(2)-6f(1/2)+6f(1/2)-9f(2) = 8+3/4`

`=>-5f(2) = 35/4`

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