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Range of f(x) =1/(1-2cosx) is (1) [1/3...

Range of `f(x) =1/(1-2cosx)` is (1) `[1/3,1]` (2) `[-1,1/3]` (3) `(-oo,-1]uu[1/3,oo)` (4) `[-1/3,1]`

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Given,` f(x) = 1/(1-2cosx) `
We know, `-1≤cosx≤1 `
`=>-2≤-2cosx≤2 `
`=> -1≤(1-2cosx)≤3 `
...
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Range of f(x)=(1)/(1-2cos x) is (1)[(1)/(3),1] (2) [-1,(1)/(3)](3)(-oo,-1]uu[(1)/(3),oo)(4)[-(1)/(3),1]

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The range of (x ^ (2) -2x + 3) / (x ^ (2) -2x-8) AA x in R is (i) (- oo, 0] uu [1, oo) (ii) [ (1) / (2), 2] (iii) (- oo, - (2) / (9)] uu [1, oo) (iv) (oo, -6] uu ([- 2, oo)

The solution set of the inequation (3)/(|x|+2) O (-1,1) O [-1,1] O (-oo,-1]uu[1,oo) O (1, oo)

(1) / (1.2) + (1.3) / (1.2.3.4) + (1.3.5) / (1.2.3.4.5.6) + .... oo

The domain of the function f(x)=((x+1)(x-3))/(x-2) is [-1,2)uu[3,oo) b. (-oo,-3)uu(2,5) c. (-oo,-3]uu[2,5] d. none of these

The domain of the function f(x)=sqrt(((x+1)(x-3))/(x-2)) is [-1,2)uu[3,oo) b. (-1,2)uu[3,oo) c. [-1,2]uu[3,oo) d. none of these

The function f: A->B defined by f(x)=-x^2+6x-8 is a bijection, if A=(-oo,\ 3] and B=(-oo,\ 1] (b) A=[-3,\ oo) and B=(-oo,\ 1] (c) A=(-oo,\ 3] and B=[1,\ oo) (d) A=[3,\ oo) and B=[1,\ oo)

lim_ (x rarr oo) {(1) / (3) + (1) / (3 ^ (2)) + (1) / (3 ^ (3)) + ...... (. 1) / (3 ^ (n))} =

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