`((3)^(-5)xx5^(-2)xx27^(2/3))/(6^2xx25^(1/2)xx49^(-1/2))`

Simplify: ((5^(-3)xx7^(4))/(7^(-2)xx5^(-6)))^((5)/(2))xx((5^(-3)xx7^(-3))/(7^(5)xx5^(2)))^((3)/(2))

Simplify: ((5^(-3)xx7^(4))/(7^(-2)xx5^(-6)))^((5)/(2))xx((5^(-3)xx7^(-3))/(7^(5)xx5^(2)))^((3)/(2))

((7^((-1/2))xx5^(2))^(2))/sqrt(25^(3))=

Find the value of n : (2^(3)xx5^(n+1)xx10^(2)xx5^(n-1))/(125xx5^(n-2)xx2^(7))=(25)/(4)

What will be the H.C.C.F.of 2^(-3)xx3^(-4)xx5^(-1) and 2^(-2)xx3^(-5)xx5^(-2)xx7^(-1)

Simplify : (3^(-3)xx6^(2)xx sqrt(98))/(5^(2)xx((1)/(25))^((1)/(3))xx(15)^(-(4)/(3))xx3^((1)/(3)))

Find the HCF of (2^(5) xx 5^(2) xx 11^(1)), (3^(2) xx 5^(3) xx 11^(2)) and (2^(4) xx 3^(6) xx 5^(1) xx 7^4)

Evaluate (i) (8^(-1)xx5^(3))/(2^(-4))( ii) (5^(-1)xx2^(-1))xx6^(-1)

(2^((1)/(3))xx5^((2)/(3)))/(2^(-(2)/(3))xx5^(-(1)/(3)))

Simplify: (9^(1/3)xx27^(-1/2))/(3^(1/6)xx3^(-2/3))