The product of first three terms of a G.P. is 1000. If 6 added to its second term and 7 added to its third term, the terms become in A.P. Find the G.P.

The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is

The sum of three consecutive numbers of a G.P. is 14. If 1 is added in first and second term each and 1 subtracted from third, the new numbers form an A.P. Find the numbers.

The 4th term of a G.P. is square of its second term, and the first term is -3. Determine its 7th term.

The product of 3rd and 8th terms of a G.P. is 243 and its 4th term is 3. Find its 7th term.

The 4 th term of a G.P.is square of its second term and the first term is -3. Find its 7 th term.

The sum of first three terms of a G.P. is (39)/(10) and their product is 1. Find the common ratio and the terms.

The term of a G.P.is square of its second term,and the first term is the first term is . Determine its Determine its term.

The fourth term of a G.P. is 4. Find product of its first seven terms.

The sum of first seven terms of an A.P is 182 . If its 4(th) term and 7^(th) term are in the ratio 1:5 then Find the A.P