" 5.समीकरण "(x+2)(3x-1)=0" Of हल- Write the set. "

Write the power set of X ={1,2}

If underset(0)overset(1)int (3x^2 +2x +k) dx = 0 , write the value of 'k'.

If x^(2//3) -7 x^(1//3) + 10 = 0 , then the set of values of x, is

If x^(2//3) -7 x^(1//3) + 10 = 0 , then the set of values of x, is

Let X={-1,0,2,5}andf:XtoR:f(x)=x^(3)+1 . Then, write f as a set of ordered pairs.

The solution set of (2cos x-1)(3+2cos x)=0 in the interval 0<=x<=2 pi is

If f: R->R is defined by f(x)={(x+2)/(x^2+3x+2) if x in R-{-1,-2}, -1 if x = -2 and 0 if x=-1. ifx=-2 then is continuous on the set

If f : R to R is defined by f (x) = {:{((x+2)/(x^(2)+3x+2), if x in R - { 1,-2}), ( -1, if x = -2) , ( 0 , if x = -1 ) :} then f is continuous on the set

If f : R rarr R is defined by f(x) = {((x+2)/(x^(2)+3x+2), x in R-{-1,-2}),(-1, x=-2),(0, x = -1):} then f is continuous on the set