log(3x+2)+log y-(3x-2)=5log2

log(3x-2)+log(3x+2)=5log2

If log_3 2+log_3 (2^x-7/2)=2log_3 (2^x-5) then x=

If log_(3)x + log_(3)y =2 + log_(3)2 and log_(3)(x+y) =2 , then

Find x, if log x^(3) - log 3x =2 log 2 + log 3 ,

If log x = (log y) / (2) = (log z) / (5), thtenx ^ (4) y ^ (3) z ^ (- 2) =

log_(2)(log_(2)(log_(3)x))=log_(2)(log_(2)(log_(2)y))=0 find (x+y)=?

Solve for x : (i) log_(10) (x - 10) = 1 (ii) log (x^(2) - 21) = 2 (iii) log(x - 2) + log(x + 2) = log 5 (iv) log(x + 5) + log(x - 5) = 4 log 2 + 2 log 3

If x^(2)+y^(2)=10xy prove that 2log(x+1)=log x+log y+2log2+log3