[5times25^(n+1)-25times5^(2n)],[5times5^(2n)+3-(25)^(n+1)=],[=]

(5^(n+3)-6times5^(n+1))/(9times5^(n)-2^(2)times5^(n))

5^(2)times25^(3)times625=(5)^(?)

Simplify the following: (3^(n)x9^(n+1))/(3^(n-1)x9^(n-1)) (ii) (5x25^(n+1)-25x5^(2n))/(5x5^(2n+3)-(25)^(n+1))

[8^(-2/3)times2^(1/2)times25^(-5/4)]÷[32^(-2/5)times125^(-5/6)] =sqrt2

The value of (5.(25)^(n+1) + 25.(5)^(2n-1))/(25.(5)^(2n) -105(25)^(n-1)) is :

Find n,if 12times^((n-1))P_3=5times^((n+1))P_3

Solve: 2.5times1.25

5^(1) xx 5^(3) xx 5^(5) xx ….5^(2n-1) = (25)^(72) Find n.

If 2^(n-7) xx 5^(n-4)=1250, find the value of n. Hint: 2^(n-4) xx 2^(-3) xx 5^(n-1)=1250 implies frac(2^(n-4) xx 5^(n-4))(2^(3))= 1250 implies (2 xx 5)^(n-4)=(10)^(4).