4x+ky+8=0&2x+2y+2=0

If 3x-ky-2=0, 2x+y+2=0 are perpendicular, then the value of k =

Find the value of k for which the following system of equations has a unique solution: 4x+ky+8=0,quad 2x+2y+2=0

If the planes 2x + 3y + 4z + 7 = 0 and 4x + ky + 8z + 1 = 0 are parallel then k =

Find the value of k if x + y - 5 = 0 2x + ky - 8 = 0 are conjugate with respect to the circle x^(2) + y^(2) - 2x - 2y -1 = 0

If system of homogenous equations x+ky-2z=0,2x+y-3z=0 and 4x+2y-kz=0 has non-trivial solution thenthe integral value of k is

The number of values of k which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 Possess a non-zero solution is

The number of values of k which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 Possess a non-zero solution is