[" 20.In order to prepare "100cm^(3)" of...

[" 20.In order to prepare "100cm^(3)" of "0.250M],[" barium chloride solution the amount of "],[BaCl_(2)*2H_(2)O" required will be- "],[(A)0.250moles],[(B)0.0025moles],[(C)2.5moles],[(D)6.1gram" of "BaC_(2).2H_(2)O]

Similar Questions

Explore conceptually related problems

In order to prepare 100cm^(3) of 0.250M barium chloride solution, the amount of BaCI_(2).2H_(2)O required will be

For decolourisation of 1.5 moles of KMnO_(4) the moles of H_(2)O_(2) requires

Number of moles of water in 488 gm of BaCl_(2).2H_(2)O are - (Ba = 137)

How many grams of H_(2)O_(2) are required to convert 0.1 moles PbS to 0.1 moles PbSO_(4) -

Calculate the number of moles of water in 610 g BaCl_(2).2H_(2)O

500 mL of 0.250 M Na_(2)SO_(4) solution is treated with 15.00 g of BaCl_(2) . Moles of BaSO_(4) formed are

The weight of (COOH)_(2). 2H_(2)O needed to prepare 500 cm^(3) of 0.1 M solution is :

What Is the number of moles of H_(2)SO_(4) required to prepare 5.0L" of a"2.0M solution of H_(2)SO_(4) ?

Amount of glucose ( C_(6)H_(22)O_(6) ) required to prepare 100 mL of 0.1 M solution is: