In a hand at Whist, what is the probability that four kings are held by a specified player?

Explanation

In a game of whist, 4 players play the gam and each player is given `13` cards.

So, total number of ways a player is given `13` cards ` = C(52,13)`

Now, there are `4` kings and we need to find the number of ways so that
all `4` kings goes to a specific player.

A specific player can be given all `4` kings and
rest of the `9` cards can be given from remaining `48` cards.

So, total number of cases in this case ` = C(4,4)*C(48,9)`

So, the required probability ` = (C(4,4)xxC(48,9))/(C(52,13)).`