`cos^6A+sin^6A=1/4(1+3cos^2 2A)` cos6A+ sin A = (1 + 3cos22A)

cos^6A-sin^6A=cos2A(1-1/4sin^2 2A)

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

(sin A sin2A + sin3A sin6A + sin4A sin13A) / (sin A cos2A + sin3A cos6A + sin4A cos13A) = tan9A

cos ^ (6) A-sin ^ (6) A = cos2A (1- (1) / (4) sin ^ (2) 2A)

sin^6A+cos^6A+3sin^2A cos^2A=\ a. 0 b. 1 c. 2 d. 3

Prove that: (cos 2A cos 3A-cos 2A cos 7A + cos A cos 10A)/(sin 4A sin 3A -sin 2A sin 5A + sin 4A sin 7A)= cot 6A cot 5A .

sin^6A+cos^6A+3sin^2A.cos^2A=