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cot x cos ^2 x - tan x sin ^2 x = 2 cot ...

`cot x cos ^2 x - tan x sin ^2 x = 2 cot 2x`

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cot x-2 cot 2x = tan x

1- (sin ^ (2) x) / (1 + cot x) + (cos ^ (2) x) / (1 + tan x) = sin x cos x

Knowledge Check

  • If sin^(2) x tan x + cos ^(2) x cot x - sin 2 x = 1 + tan x + cot x x in (0, pi) then x =

    A
    `(3 pi)/( 12), (5 pi)/(12)`
    B
    `(5 pi)/( 12), (7 pi)/(12)`
    C
    `(7 pi)/( 12), (11 pi)/( 12)`
    D
    `(9 pi)/(12), (9 pi)/( 12)`

  • sin 2x (tan x + cot x) = ?

    A
    `sin x cos x`
    B
    `cosec x sec x`
    C
    `2tan(2x)`
    D
    `2`

  • If tan (cot x) = cot (tan x), then sin 2x is equal to :

    A
    `2/((2n+1)pi)`
    B
    `(4)/((2n+1) pi)`
    C
    `(2)/(n(n+1)pi)`
    D
    `(4)/(n(n+1)pi)`

    • Similar Questions

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    1- (sin ^ (2) x) / (1 + cot x) - (cos ^ (2) x) / (1 + tan x) = sin x cos x

    tan^(2)2x + cot^(2)2x + 2tan 2x + 2 cot 2x=6

    Solve : (i) cos 3theta + 8 cos^(3) theta = 0 (ii) "tan" (pi cot x) = cot (pi tan x) (iii) 4 cos^(2) x sin x-2 "sin"^(2) x = 3 sin x

    int( d x)/(sin ^(2) x cos ^(2) x) equals a) tan x+cot x+C b) tan x-cot x+C c) tan x cot x+C d) tan x-cot 2 x+C

    Let P(x) = ((1- cos 2 x + sin 2x)/(1+ cos2x + sin2x))^(2) + ((1+ cot x + cot^(2) x)/( 1+ tan x+ tan^(2) x) ) , then the minimum value of P(x) equals

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