`cot x cos ^2 x - tan x sin ^2 x = 2 cot 2x`

cot x-2 cot 2x = tan x

If sin^(2) x tan x + cos ^(2) x cot x - sin 2 x = 1 + tan x + cot x x in (0, pi) then x =

sin 2x (tan x + cot x) = ?

1- (sin ^ (2) x) / (1 + cot x) + (cos ^ (2) x) / (1 + tan x) = sin x cos x

1- (sin ^ (2) x) / (1 + cot x) - (cos ^ (2) x) / (1 + tan x) = sin x cos x

tan^(2)2x + cot^(2)2x + 2tan 2x + 2 cot 2x=6

Solve : (i) cos 3theta + 8 cos^(3) theta = 0 (ii) "tan" (pi cot x) = cot (pi tan x) (iii) 4 cos^(2) x sin x-2 "sin"^(2) x = 3 sin x

int( d x)/(sin ^(2) x cos ^(2) x) equals a) tan x+cot x+C b) tan x-cot x+C c) tan x cot x+C d) tan x-cot 2 x+C

Let P(x) = ((1- cos 2 x + sin 2x)/(1+ cos2x + sin2x))^(2) + ((1+ cot x + cot^(2) x)/( 1+ tan x+ tan^(2) x) ) , then the minimum value of P(x) equals