The mean deviation for `n` observations `x_1, x_2, ......... , x_n` from their mean ` X ` is given by (a)`sum_(i=1)^n(x_i- X )` (b) `1/nsum_(i=1)^n(x_i- X )` (c) `sum_(i=1)^n(x_i- X )^2` (d) `1/nsum_(i=1)^n(x_i- X )^2`

Explanation

To find the mean deviation for `n` observations \( x_1, x_2, \ldots, x_n \) from their mean \( \bar{X} \), we can follow these steps:

### Step 1: Calculate the Mean
The mean \( \bar{X} \) of the observations is calculated using the formula:
\[ \bar{X} = \frac{x_1 + x_2 + \ldots + x_n}{n} = \frac{1}{n} \sum_{i=1}^{n} x_i \]

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