A particle `(q , m)` moves under the action of electric field `vec(E)=(A-Bx)`i where A and B are positive constant.If velocity of particle at `x`=0 is zero then maximum velocity attained by particle is ???

A particle of mass 2 kg moves in the xy plane under the action of a constant force vec(F) where vec(F)=hat(i)-hat(j) . Initially the velocity of the particle is 2hat(j) . The velocity of the particle at time t is

A particle of mass m moves in a circular orbit under the central potential field, U(r)==-C/r, where C is a positive constant. The correct radius -velocity graph of the particle's motion is.

A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

A particle of charge q and mass m starts moving from the origin under the action of an electric field vecE=E_0 hat i and vec B=B_0 hat i with velocity vec v=v_0 hat j . The speed of the particle will become 2v_0 after a time

A particle starts from rest and moves with a constant acceleration of 4 m//s^(2) for 10 s , then it moves under constant seceleration and stops in 20 s . Find (a) the maximum velocity attained by the particle (b) the total distance traveled and (c ) the distance/distances from the origin, when the particle is moving at half the maximum velocity.

A particle with specific charge q//m moves rectilinerarly due to an electric field E = E_(0) - ax , where a is a positive constant, x is the distance from the point where the particle was initially at rest. Find: (a) the distance covered by the particle till the moment it came to a standstill, (b) the acceleration of the particle at that moment.

A charged particle (q,m) is released from origin in an electric field E = alpha - beta x where alpha and beta are constants and x is distance from origin. Find the velocity of particle in terms of x and maximum displacement of the particle.