Home
Class 12
MATHS
A line bisecting the ordinate PN of a po...

A line bisecting the ordinate PN of a point `P(at^2,2at),6 gt 0` , on the parabola `y^2=4ax` is drawn parallel to the axis to meet the curve at Q. If NQ meets the tangent at the vertex at the point T, then the coordinates of T are:

Promotional Banner

Similar Questions

Explore conceptually related problems

A line bisecting the ordinate PN of a point P(at^(2),2at), t>0,on parabola y^(2)=4ax is drawn parallel to the axis to meet curve at Q.If NO meets meets the tangent at the vertex at Point T.Then the coordinates of T are:

Let N be the foot of perpendicular to the x- axis from point P on the parabola y^(2)=4ax. A straight line is drawn parallel to the axis which bisects PN and cuts the curve at Q; if NO meets the tangent at the vertex at a point then prove that AT=(2)/(3)PN.

Foot of perpendicular from point P on the parabola y^(2)=4ax to the axis is N. A straight line is drawn parallel to the axis which bisects PN and cuts the curve at Q. If NQ meets the tangent at the vertex A at a point T, then (PN)/(AT) =__________.

A straight line is drawn parallel to the x-axis to bisect an ordinate PN of the parabola y^(2) = 4ax and to meet the curve at Q. Moreever , NQ meets the tangent at the vertex A of the parabola at T. AT= Knp , then k is equal to

If the tangent at a point P with parameter t on the curve x=4t^(2)+3,y=8t^(3)-1t in R meets the curve again at a point Q, then the coordinates of Q are

If a tangent to the parabola y^(2)=4ax meets the x -axis at T and intersects the tangents at vertex A at P, and rectangle TAPQ is completed,then find the locus of point Q.

Show that the length of the tangent to the parabola y^2 = 4ax intercepted between its point of contact and the axis of the parabola is bisected by the tangent at the vertex.

The tangent at a point P on the parabola y^(2)=8x meets the directrix of the parabola at Q such that distance of Q from the axis of the parabola is 3. Then the coordinates of P cannot be

If a tangent to the parabola y^(2)=4ax meets the axis of the parabola in T and the tangent at the vertex A in Y ,and the rectangle TAYG is completed,show that the locus of G is y^(2)+ax=0.