For a dipole `q=2times10^(-6)`C and `d=1cm` .The external electric field if maximum torque experienced by this dipole `10^(-2)`Nm is.........

For a dipole q= 2xx10^(-6)C and d= 0.01m . Calculate the maximum torque for this dipole if E= 5xx10^(5)N//C

An electric dipole consists of two opposite charges each 0.05 mu C separated by 30 mm. The dipole is placed in an uniform external electric field of 10^(6)NC^(-1) . The maximum torque exerted by the field on the dipole is

An electric dipole cosnists of two opposite charges of magnitude 1muC separated by a distance of 2cm .The dipole is placed in an electric filled 10^(-5)Vm^(-1) .The maximum torque that the field exert on the dipole is

An electric dipole with dipole moment bar(p)=2times10^(-8)hat i C-m is kept in a region with electric field 100N/C i .The magnitude of torque due to electrostatic force on the dipole is

Electric dipole is placed in external electric field. When the potential energy of dipole is maximum?

An electric dipole consists of two opposite charges of magnitude 1 muC (micro-coulomb) separated by a distance of 2 cm . The dipole is placed in an electric field of 10^(5) V m^(-1) . (a) What maximum torque does the field exert on the dipole ? (b) How much work must an external agent do to turn the dipole end for end , starting from a position of alignment theta = 0 ?

An electric dipole consisting of two opposite charges of 2xx10^(-6)C each separated by a distance of 3 cm is placed in an electirc field of 2xx10^(5)N//C . The maximum torque on the dipole is will be

An electric dipole located in uniform electric field in stable equilibrium position . It is now slowly rotated to the position of unstable equilibrium . Work donw by the external agent in the process is numerically how may times the maximum electric torque experienced by the dipole during the process ?