^^_(m) of 1MCH_(3)COOH is 20Scm^(2)mol^(-1) and ^^_(m)^( oo) is 400S cm^(2) mol- 1 The pH of solution will be : a) 1.30 b) 2.30 c) 3.30 (は) 1.70

Calculate degree of dissocation of 0.02 M acetic acid at 298K. Given that Lamda_(m) (CH_(3)COOH)= 17.37 S cm^(2) mol^(-1), lamda_(m)^(@) (H^(+)) = 345.8 S cm^(2) mol^(-1), lamda_(m)^(@) (CH_(3)COO^(-)) = 40.2S cm^(2) mol^(-1)

What is the value of pK_(b)(CH_(3)COO^(c-)) if wedge^(@)._(m)=390 S cm^(-1) mol ^(-1) and wedge_(m)=7.8 S cm^(2) mol^(-1) for 0.04 M of CH_(3)COOH at 25^(@)C ?

Molar conductance of 2 M H_(2)A acid is 10 S cm^(2) mol^(-1) Molar conductance of H_(2)A at infinit e dilution is 400 S cm^(2) mol^(-1) which statement is/are correct?

Calculate degree of dissociation of 0.02 M acetic acid at 298 K given that mho_(m)(CH_(3)COOH)=17.37 cm^(2) mol^(-1),lambda_(m)^(@)(H+)=345.8 S cm^(2) mol^(-1), lambda_(m)^(@)(CH_(3)COO^(-))=40.2 Scm^(2) mol^(-1)

Calculate the degree of dissociation (alpha) of acetic acid if its molar conductivity (^^_(m)) is 39.05 S cm^(2) mol^(-1) Given lamda^(@) (H^(+)) = 349.6 cm^(2) mol^(-1) and lamda^(2) (CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)

The values of ^^_(m)^(oo) for KCl and KNO_(3) are 149.86 and 154.96Omega^(-1)cm^(2)"mol"^(-1) . Also lambda_(Cl)^(oo) is 71.44 ohm^(-1)cm^(2) "mol"^(-1) . The value of lambda_(NO_(3)^(-))^(oo) is

Rate constant k = 1.2 xx 10^(3) mol^(-1) L s^(-1) and E_(a) = 2.0 xx 10^(2) kJ mol^(-1) . When T rarr oo :

Hydrofluoric acid is a weak acid. At 25^(@)C , the molar conductivity of 0.002 M HF is 176.2 ohm^(-1) cm^(2) mol^(-1) . If its Lamda_(m)^(oo) = 405.2 ohm^(-1) cm^(2) mol^(-1) , calculate its degree of dissociation and equilibrium constant at the given concentration.