13.If a mass m is suspended with a spring then we get x extension Now we attech an another mass (M) with the previous one and again oscillate was what will be the time period of the osullations of the system?

The time period of small oscillations of mass m :-

A mass M is suspended from a spring of negiliglible mass the spring is pulled a little and then released so that the mass executes simple harmonic oscillation with a time period T If the mass is increases by m the time period because ((5)/(4)T) ,The ratio of (m)/(M) is

A system of springs with their spring constants are as shown in figure. What is the frequency of oscillations of the mass m ?

One mass m is suspended from a spring. Time period of oscilation is T. now if spring is divided into n pieces & these are joined in parallel order then time period of oscillation if same mass is suspended.

A mass suspended from a spring of spring constant k is made to oscillate with a time period T. Now, the spring is cut into three equal parts and the mass is suspended from one of the parts. What will be the new time period of oscillations?

A mass m is suspended from a spring of force constant k and just touches another identical spring fixed to the floor as shown in the fig. The time period of small oscillations is

The time period of a mass suspended from a spring is T if the spring is cut in to equal part and the same mass is suspended from one of the pert then the time period will be

Let T_(1) and T_(2) be the time periods of two springs A and B when a mass m is suspnded from them seperately. Now both the springs are connected in parallel and same mass m is suspended with them. Now let T be the time period in this position. Then -