The area of the triangle whose vertices are the roots of `z^3+iz^2+2i=0` is ------

The area of the triangle whose vertices are i, omega omega^(2)

The area of the triangle whose vertices are represented by 0,z,ze^(i alpha)

The area of the triangle with vertices affixed at z, iz, z(1 +i) is:

The area of the triangle whose vertices are represented by 0,z,z e^(ialpha)

If |z_1 |=|z_2|=|z_3| = 1 and z_1 +z_2+z_3 =0 then the area of the triangle whose vertices are z_1 ,z_2 ,z_3 is

If z is a complex number, then the area of the triangle (in sq. units) whose vertices are the roots of the equation z^(3)+iz^(2)+2i=0 is equal to (where, i^(2)=-1 )

If z is a complex number, then the area of the triangle (in sq. units) whose vertices are the roots of the equation z^(3)+iz^(2)+2i=0 is equal to (where, i^(2)=-1 )

The area of triangle with vertices affixed at z , iz , z(1+i) is