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If for a sample of size 60, we have the following information `sumx_i^2=18000 \ and \ sumx_i^2=960` , then the variance is (a) 6.63 (b) 16 (c) 22 (d) 44

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Required variance is,
`=(sum(x_i)^2)/n​​−((x_i​​)/n)^2`
`=(18000)/(60)​−((960​)/(60))^2`
`=300−256`
`=44`
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