In an acute angle triangle ABC, AD, BE and CF are the altitudes, then `(EF)/a+(FD)/b+(DE)/c` is equal to -

In an acute angled triangle ABC , let AD, BE and CF be the perpendicular opposite sides of the triangle. The ratio of the product of the side lengths of the triangles DEF and ABC , is equal to

In an acute angled triangle ABC , let AD, BE and CF be the perpendicular opposite sides of the triangle. The ratio of the product of the side lengths of the triangles DEF and ABC , is equal to

In triangle ABC, AD, BE and CF are altitudes. Prove I, that, AD + BE + CF lt AB + BC + CA

In triangle ABC, AD, BE and CF are altitudes. Prove I, that, AD + BE + CF lt AB + BC + CA

In an acute angled triangle ABC, let AD,BE and CF be the perpendicular opposite sides of the triangle.The ratio of the product of the side lengths of the triangles DEF and ABC, is equal to

If in a triangle ABC, AD, BE and CF are the altitudes and R is the circumradius, then the radius of the circumcircle of Delta DEF is

In a triangle ABC, AD, BE and CF are the altitudes and R is the circum radius, then the radius of the circle DEF is

Consider an acute angled Delta ABC. Let AD, BE and CF be the altitudes drawn from the vertice to the opposite sides. Prove that : (EF)/(a)+ (FD)/(b)+ (DE)/(c)= (R+r)/(R ).