A spring balance has a scale that reads from 0 to 50kg. The length of the scale is 20cm. A body suspended from this spring, when displaced and released, oscillates with period of 0.60s. What is the weight of the body?

Explanation

`M = 50 kg, y = 20 cm = 0.2m, T = 0.60 s`
`F = ky` or `Mg = ky` or `k = (Mg)/(0.2) = (50 xx 9.8)/(0.2) Nm^(-1)`
or `K = 2450 Nm^(-1)`
Now, `T = 2pi sqrt((m)/(k))`
or `T^(2) = 4pi^(2) (m)/(k)` or `m = (T^(2)k)/(4pi^(2))`
or `m = (0.6 xx 0.6 xx 2460 xx 49)/(4 xx 484) kg = 22.3 kg`
`rarr mg = 22.3 xx 9.8 N = 218.5 N = 22.3 kgf`.