The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0m. If the piston moves with simple harmonic motion with an angular frequency of `200rev//`min., what is its maximum speed ?

Explanation

Stroke of piston =2 times the amplitude
Let A = amplitude, stroke = 1m
`:. rArr A = (1)/(2)m`
Angular frequency, `omega = 200 rad//min`.
`V_(max) = ?`
We know that the maximum speed of the block when the amplitude is A,
`V_(max) = omega A = 200 xx (1)/(2) = 100 m//min`.
`=(100)/(60) = (5)/(3) ms^(-1) = 1.67 ms^(-1)`