The mass fo an electron is ` 9. 1 xx 10^(-31) kg`. If its K.E. is `3. 0 xx 10 ^(25) J`. Calculate its wavelength .

Explanation

since K. E. =` 1//2 mv^(2)`
`v=((2K.E.)/m)^(1//2) = ((2xx3.0xx10^(-25)kg^(2)m^(2)s^(-2))/(9.1xx10^(-31) kg))^(1//2)`
`812ms^(-1)`
`lamda=h/(mv)=(6.626xx10^(-34)Js)/((9.1xx10^(-31)kg)(812ms^(-1)))`
` 8967xx10^(-10)m = 896. 7 nm`