Give the number of electrons in the species `H_(2)^(+), H_(2)` and `O_(2)^(o+)`

Explanation

Number of electrons present in hydrogen molecule `(H_(2))` = 1 + 1 = 2
number of electrons in `H_(2)^(+) = 2-1= 1 `
`H_(2):`
number of electorn in `H_(2) = 1+1 =2 `
`O_(2)^(+)`
number of electrons present in oxygen molecule `(O_(2))` = 8+8 = 16
number of electrons in `O_(2)^(+)` = 16-1=15