The diameter of zinc atom is `2.6 A`. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of `1.6 cm` if the zinc atoms are arranged side by side lengthwise.

Explanation

(a) Radius of zinc atom = `("Diameter")/(2)`
= `(2.6 Å)/(2)`
= `1.3 xx 10^(-10) m `
= `130 xx 10^(-12) m = 130 `pm
(b) Length of the arrangement = `1.6` cm
= `1.6 xx 10^(-2)` m
Diameter of zinc atom = `2.6 xx 10^(-10) m `
`therefore` Number of zinc atoms present in the arrangement
= `(1.6 xx 10^(-2) m)/(2.6 xx 10^(-10 m )`
= `0.6153 xx 10^(8) m `
= `6.153 xx 10^(7) `