An ion with mass number `37` possesses one unit of negative charge. If the ion contains `11.1%` more neutrons than the electrons, find symbol of the ion.

Explanation

Let the number of electrons in the ion carrying a negative charge be x.
Then,
Number of neutrons present
`= x + 11.1%` of `x`
`= x + 0.111 x`
`= 1.111 x`
Number of electrons in the neutral atom = (x – 1)
(When an ion carries a negative charge, it carries an extra electron)
`:.` Number of protons in the neutral atom = x – 1
Given,
Mass number of the ion = 37
`:. (x - 1) + 1.111 x = 37`
`2.111x = 38`
`x = 18`
`:.` The symbol of the ion is `._(17)^(37)Cl^(-)`