The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists:
` 1. n=4 , l=2 , m_(i) =-2, m_(s) =-1//2 `
`2. n=3 , l=2 , m_(l) =1 , m_(s) =+1//2`
3.`n=4 , l=2 ,m_(l)=-2, m_(s) =-1//2`
4. ` n=3 , l= 2, m_(i) =-1 , m_(s) = +1//2`
5. ` n=3 , l=1 , m_(l) =-1 , m_(s) = +1//2`
6. `n=4 , l= 1 , m_(l) =0 , m_(s) =+1//2`

Explanation

from Heisenberg's uncertainty principal
` Deltax xx Deltap= h/(4pi) Rightarrow Deltap=1/(Deltap)=1/(Deltax). h/(4pi)`
where ,
`Deltax` = uncertainrty in position of the electron
` Deltap` = uncertainty in momentum of the electron
substituting the values in the expression of `Deltap`
` Deltap=1/(0.002nm)xx(6.626xx10^(-34) Js)/(4xx(.14))`
` =1/(2xx 10^(-12) m) xx (6. 626xx 10^(-34) Js)/(4xx 3.14)`
` 2.637xx 10^(-23) Jsm^(-1)`
`Deltap= 2.637xx 10^(-23) kgms^(-1) (1J =1kgms^(2) s^(-1))`
uncertainty in the momentum of the electron `=2.637xx 10^(-23) kgms^(-1)`
Actual momentum =`h/(4pi_(m)xx0.05 nm)`
`(6.626xx 10^(-34) Js)/(4xx3.14 xx 5.0 xx 10^(-11) m )`
`1.055 xx 10^(-24) kgms ^(-1)`
Since the magnitude of the actual momentum is smaller than the uncertainty, the value cannot be defined.