Calculate the molarity of a solution containing `5 g` of NaOH in `450 mL` solution.

Explanation

Moles of `NaOH=(5)/(40g" "mol^(-1))=0.125mol`
Volume of the solution in litres `=450mL//1000" mL "L^(-1)`
Molarity `=(0.125" mol "xx1000" mL "L^(-1))/(450mL)=0.278M`
`=0.278" mol "L^(-1)`
`=0.278" mol "dm^(-3)`.